函数简介

程序示例

函数简介

函数名: cgets（在VC++6.0下为_cgets）

功 能: 从键盘得到一个字符串

用 法: char *_cgets( char *buffer );

所属库：conio.h

相关函数：getch、getche、gets、getchar、_cgetws

程序示例

#include <conio.h>

#include <stdio.h>

int main(void)

{

char buffer[83];

char *p;

/* There's space for 80 characters plus the NULL terminator */

buffer[0] = 81;

printf("Input some chars:");

p = cgets(buffer);

printf("\cgets read %d characters: \\"%s\\"\", buffer[1], p);

printf("The returned pointer is %p, buffer[0] is at %p\", p, &buffer);

/* Leave room for 5 characters plus the NULL terminator */

buffer[0] = 6;

printf("Input some chars:");

p = cgets(buffer);

printf("\cgets read %d characters: \\"%s\\"\", buffer[1], p);

printf("The returned pointer is %p, buffer[0] is at %p\", p, &buffer);

return 0;

}

下面的例子来自MSDN

#include <conio.h>

#include <stdio.h>

#include <errno.h>

int main( void )

{

char buffer[83] = { 80 }; // Maximum characters in 1st byte

char *result;

printf( "Input line of text, followed by carriage return:\");

// Input a line of text:

result = _cgets( buffer ); // C4996

// Note: _cgets is deprecated; consider using _cgets_s

if (!result)

{

printf( "An error occurred reading from the console:"

" error code %d\", errno);

}

else

{

printf( "\Line length = %d\Text = %s\",

buffer[1], result );

}

}